z^2+122z+121=0

Solution for z^2+122z+121=0 equation:

z^2+122z+121=0

a = 1; b = 122; c = +121;
Δ = b2-4ac
Δ = 1222-4·1·121
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(122)-120}{2*1}=\frac{-242}{2}
=-121
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(122)+120}{2*1}=\frac{-2}{2}
=-1
$